3(m-5)=7-2(m-3)

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Solution for 3(m-5)=7-2(m-3) equation: 



3(m-5)=7-2(m-3)

We move all terms to the left:

3(m-5)-(7-2(m-3))=0

We multiply parentheses

3m-(7-2(m-3))-15=0



We calculate terms in parentheses: -(7-2(m-3)), so:

7-2(m-3)

determiningTheFunctionDomain
-2(m-3)+7

We multiply parentheses

-2m+6+7

We add all the numbers together, and all the variables

-2m+13

Back to the equation:

-(-2m+13)



We get rid of parentheses

3m+2m-13-15=0

We add all the numbers together, and all the variables

5m-28=0

We move all terms containing m to the left, all other terms to the right

5m=28

m=28/5

m=5+3/5

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