3(m-6)+5=2(m+1)

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Solution for 3(m-6)+5=2(m+1) equation: 



3(m-6)+5=2(m+1)

We move all terms to the left:

3(m-6)+5-(2(m+1))=0

We multiply parentheses

3m-(2(m+1))-18+5=0



We calculate terms in parentheses: -(2(m+1)), so:

2(m+1)

We multiply parentheses

2m+2

Back to the equation:

-(2m+2)



We add all the numbers together, and all the variables

3m-(2m+2)-13=0

We get rid of parentheses

3m-2m-2-13=0

We add all the numbers together, and all the variables

m-15=0

We move all terms containing m to the left, all other terms to the right

m=15

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