3(m-6)=4(2m+1)

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Solution for 3(m-6)=4(2m+1) equation: 



3(m-6)=4(2m+1)

We move all terms to the left:

3(m-6)-(4(2m+1))=0

We multiply parentheses

3m-(4(2m+1))-18=0



We calculate terms in parentheses: -(4(2m+1)), so:

4(2m+1)

We multiply parentheses

8m+4

Back to the equation:

-(8m+4)



We get rid of parentheses

3m-8m-4-18=0

We add all the numbers together, and all the variables

-5m-22=0

We move all terms containing m to the left, all other terms to the right

-5m=22

m=22/-5

m=-4+2/5

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