3(m-8)+7=5(m+2)-2m-27

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Solution for 3(m-8)+7=5(m+2)-2m-27 equation: 



3(m-8)+7=5(m+2)-2m-27

We move all terms to the left:

3(m-8)+7-(5(m+2)-2m-27)=0

We multiply parentheses

3m-(5(m+2)-2m-27)-24+7=0



We calculate terms in parentheses: -(5(m+2)-2m-27), so:

5(m+2)-2m-27

We add all the numbers together, and all the variables

-2m+5(m+2)-27

We multiply parentheses

-2m+5m+10-27

We add all the numbers together, and all the variables

3m-17

Back to the equation:

-(3m-17)



We add all the numbers together, and all the variables

3m-(3m-17)-17=0

We get rid of parentheses

3m-3m+17-17=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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