3(n+1)+2(n-1)=6

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Solution for 3(n+1)+2(n-1)=6 equation: 



3(n+1)+2(n-1)=6

We move all terms to the left:

3(n+1)+2(n-1)-(6)=0

We multiply parentheses

3n+2n+3-2-6=0

We add all the numbers together, and all the variables

5n-5=0

We move all terms containing n to the left, all other terms to the right

5n=5

n=5/5

n=1

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