3(n+1)+4(n+2)=39

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Solution for 3(n+1)+4(n+2)=39 equation: 



3(n+1)+4(n+2)=39

We move all terms to the left:

3(n+1)+4(n+2)-(39)=0

We multiply parentheses

3n+4n+3+8-39=0

We add all the numbers together, and all the variables

7n-28=0

We move all terms containing n to the left, all other terms to the right

7n=28

n=28/7

n=4

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