3(n+1)-(-n-2)=2(2n+1)+3

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Solution for 3(n+1)-(-n-2)=2(2n+1)+3 equation:


Simplifying
3(n + 1) + -1(-1n + -2) = 2(2n + 1) + 3

Reorder the terms:
3(1 + n) + -1(-1n + -2) = 2(2n + 1) + 3
(1 * 3 + n * 3) + -1(-1n + -2) = 2(2n + 1) + 3
(3 + 3n) + -1(-1n + -2) = 2(2n + 1) + 3

Reorder the terms:
3 + 3n + -1(-2 + -1n) = 2(2n + 1) + 3
3 + 3n + (-2 * -1 + -1n * -1) = 2(2n + 1) + 3
3 + 3n + (2 + 1n) = 2(2n + 1) + 3

Reorder the terms:
3 + 2 + 3n + 1n = 2(2n + 1) + 3

Combine like terms: 3 + 2 = 5
5 + 3n + 1n = 2(2n + 1) + 3

Combine like terms: 3n + 1n = 4n
5 + 4n = 2(2n + 1) + 3

Reorder the terms:
5 + 4n = 2(1 + 2n) + 3
5 + 4n = (1 * 2 + 2n * 2) + 3
5 + 4n = (2 + 4n) + 3

Reorder the terms:
5 + 4n = 2 + 3 + 4n

Combine like terms: 2 + 3 = 5
5 + 4n = 5 + 4n

Add '-5' to each side of the equation.
5 + -5 + 4n = 5 + -5 + 4n

Combine like terms: 5 + -5 = 0
0 + 4n = 5 + -5 + 4n
4n = 5 + -5 + 4n

Combine like terms: 5 + -5 = 0
4n = 0 + 4n
4n = 4n

Add '-4n' to each side of the equation.
4n + -4n = 4n + -4n

Combine like terms: 4n + -4n = 0
0 = 4n + -4n

Combine like terms: 4n + -4n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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