3(n+1)-2=2(n+1)+n+1

Solution for 3(n+1)-2=2(n+1)+n+1 equation:

3(n+1)-2=2(n+1)+n+1

We move all terms to the left:

3(n+1)-2-(2(n+1)+n+1)=0

We multiply parentheses

3n-(2(n+1)+n+1)+3-2=0


We calculate terms in parentheses: -(2(n+1)+n+1), so:

2(n+1)+n+1

We add all the numbers together, and all the variables

n+2(n+1)+1

We multiply parentheses

n+2n+2+1

We add all the numbers together, and all the variables

3n+3

Back to the equation:

-(3n+3)


We add all the numbers together, and all the variables

3n-(3n+3)+1=0

We get rid of parentheses

3n-3n-3+1=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation