3(n+1)-2=4(n+3)

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Solution for 3(n+1)-2=4(n+3) equation:


Simplifying
3(n + 1) + -2 = 4(n + 3)

Reorder the terms:
3(1 + n) + -2 = 4(n + 3)
(1 * 3 + n * 3) + -2 = 4(n + 3)
(3 + 3n) + -2 = 4(n + 3)

Reorder the terms:
3 + -2 + 3n = 4(n + 3)

Combine like terms: 3 + -2 = 1
1 + 3n = 4(n + 3)

Reorder the terms:
1 + 3n = 4(3 + n)
1 + 3n = (3 * 4 + n * 4)
1 + 3n = (12 + 4n)

Solving
1 + 3n = 12 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
1 + 3n + -4n = 12 + 4n + -4n

Combine like terms: 3n + -4n = -1n
1 + -1n = 12 + 4n + -4n

Combine like terms: 4n + -4n = 0
1 + -1n = 12 + 0
1 + -1n = 12

Add '-1' to each side of the equation.
1 + -1 + -1n = 12 + -1

Combine like terms: 1 + -1 = 0
0 + -1n = 12 + -1
-1n = 12 + -1

Combine like terms: 12 + -1 = 11
-1n = 11

Divide each side by '-1'.
n = -11

Simplifying
n = -11

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