3(n+1)-2=4(n-4)-(n-11)

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Solution for 3(n+1)-2=4(n-4)-(n-11) equation:


Simplifying
3(n + 1) + -2 = 4(n + -4) + -1(n + -11)

Reorder the terms:
3(1 + n) + -2 = 4(n + -4) + -1(n + -11)
(1 * 3 + n * 3) + -2 = 4(n + -4) + -1(n + -11)
(3 + 3n) + -2 = 4(n + -4) + -1(n + -11)

Reorder the terms:
3 + -2 + 3n = 4(n + -4) + -1(n + -11)

Combine like terms: 3 + -2 = 1
1 + 3n = 4(n + -4) + -1(n + -11)

Reorder the terms:
1 + 3n = 4(-4 + n) + -1(n + -11)
1 + 3n = (-4 * 4 + n * 4) + -1(n + -11)
1 + 3n = (-16 + 4n) + -1(n + -11)

Reorder the terms:
1 + 3n = -16 + 4n + -1(-11 + n)
1 + 3n = -16 + 4n + (-11 * -1 + n * -1)
1 + 3n = -16 + 4n + (11 + -1n)

Reorder the terms:
1 + 3n = -16 + 11 + 4n + -1n

Combine like terms: -16 + 11 = -5
1 + 3n = -5 + 4n + -1n

Combine like terms: 4n + -1n = 3n
1 + 3n = -5 + 3n

Add '-3n' to each side of the equation.
1 + 3n + -3n = -5 + 3n + -3n

Combine like terms: 3n + -3n = 0
1 + 0 = -5 + 3n + -3n
1 = -5 + 3n + -3n

Combine like terms: 3n + -3n = 0
1 = -5 + 0
1 = -5

Solving
1 = -5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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