3(n+1)=2(n+1)+n

Solution for 3(n+1)=2(n+1)+n equation:

3(n+1)=2(n+1)+n

We move all terms to the left:

3(n+1)-(2(n+1)+n)=0

We multiply parentheses

3n-(2(n+1)+n)+3=0


We calculate terms in parentheses: -(2(n+1)+n), so:

2(n+1)+n

We add all the numbers together, and all the variables

n+2(n+1)

We multiply parentheses

n+2n+2

We add all the numbers together, and all the variables

3n+2

Back to the equation:

-(3n+2)


We get rid of parentheses

3n-3n-2+3=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation