3(n+1)=2(n+10)

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Solution for 3(n+1)=2(n+10) equation: 



3(n+1)=2(n+10)

We move all terms to the left:

3(n+1)-(2(n+10))=0

We multiply parentheses

3n-(2(n+10))+3=0



We calculate terms in parentheses: -(2(n+10)), so:

2(n+10)

We multiply parentheses

2n+20

Back to the equation:

-(2n+20)



We get rid of parentheses

3n-2n-20+3=0

We add all the numbers together, and all the variables

n-17=0

We move all terms containing n to the left, all other terms to the right

n=17

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