3(n+1)=2(n+4)

Solution for 3(n+1)=2(n+4) equation:

Simplifying
3(n + 1) = 2(n + 4)

Reorder the terms:
3(1 + n) = 2(n + 4)
(1 * 3 + n * 3) = 2(n + 4)
(3 + 3n) = 2(n + 4)

Reorder the terms:
3 + 3n = 2(4 + n)
3 + 3n = (4 * 2 + n * 2)
3 + 3n = (8 + 2n)

Solving
3 + 3n = 8 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
3 + 3n + -2n = 8 + 2n + -2n

Combine like terms: 3n + -2n = 1n
3 + 1n = 8 + 2n + -2n

Combine like terms: 2n + -2n = 0
3 + 1n = 8 + 0
3 + 1n = 8

Add '-3' to each side of the equation.
3 + -3 + 1n = 8 + -3

Combine like terms: 3 + -3 = 0
0 + 1n = 8 + -3
1n = 8 + -3

Combine like terms: 8 + -3 = 5
1n = 5

Divide each side by '1'.
n = 5

Simplifying
n = 5