3(n+1)=4(n+5)

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Solution for 3(n+1)=4(n+5) equation: 



3(n+1)=4(n+5)

We move all terms to the left:

3(n+1)-(4(n+5))=0

We multiply parentheses

3n-(4(n+5))+3=0



We calculate terms in parentheses: -(4(n+5)), so:

4(n+5)

We multiply parentheses

4n+20

Back to the equation:

-(4n+20)



We get rid of parentheses

3n-4n-20+3=0

We add all the numbers together, and all the variables

-1n-17=0

We move all terms containing n to the left, all other terms to the right

-n=17

n=17/-1

n=-17

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