3(n+1)=5(n-5)

Solution for 3(n+1)=5(n-5) equation:

Simplifying
3(n + 1) = 5(n + -5)

Reorder the terms:
3(1 + n) = 5(n + -5)
(1 * 3 + n * 3) = 5(n + -5)
(3 + 3n) = 5(n + -5)

Reorder the terms:
3 + 3n = 5(-5 + n)
3 + 3n = (-5 * 5 + n * 5)
3 + 3n = (-25 + 5n)

Solving
3 + 3n = -25 + 5n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-5n' to each side of the equation.
3 + 3n + -5n = -25 + 5n + -5n

Combine like terms: 3n + -5n = -2n
3 + -2n = -25 + 5n + -5n

Combine like terms: 5n + -5n = 0
3 + -2n = -25 + 0
3 + -2n = -25

Add '-3' to each side of the equation.
3 + -3 + -2n = -25 + -3

Combine like terms: 3 + -3 = 0
0 + -2n = -25 + -3
-2n = -25 + -3

Combine like terms: -25 + -3 = -28
-2n = -28

Divide each side by '-2'.
n = 14

Simplifying
n = 14