3(n+11)-5=-2(n-12)+9

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Solution for 3(n+11)-5=-2(n-12)+9 equation: 



3(n+11)-5=-2(n-12)+9

We move all terms to the left:

3(n+11)-5-(-2(n-12)+9)=0

We multiply parentheses

3n-(-2(n-12)+9)+33-5=0



We calculate terms in parentheses: -(-2(n-12)+9), so:

-2(n-12)+9

We multiply parentheses

-2n+24+9

We add all the numbers together, and all the variables

-2n+33

Back to the equation:

-(-2n+33)



We add all the numbers together, and all the variables

3n-(-2n+33)+28=0

We get rid of parentheses

3n+2n-33+28=0

We add all the numbers together, and all the variables

5n-5=0

We move all terms containing n to the left, all other terms to the right

5n=5

n=5/5

n=1

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