3(n+2)+(n*0.5)=2(n+1)-14

Solution for 3(n+2)+(n*0.5)=2(n+1)-14 equation:

3(n+2)+(n*0.5)=2(n+1)-14

We simplify the equation to the form, which is simple to understand 
3(n+2)+(n*0.5)=2(n+1)-14

Reorder the terms in parentheses
+(+3n+6)+( + 0.5n)=2*(n+1)-14

Remove unnecessary parentheses
+3n+6+( + 0.5n+)=+2+*(+n+1+)-14

Remove unnecessary parentheses
+3n+6 + 0.5n=+2+*(+n+1+)-14

Reorder the terms in parentheses
+3n+6 + 0.5n=+(+2n+2)-14

Remove unnecessary parentheses
+3n+6 + 0.5n=+2n+2-14

We move all terms containing n to the left and all other terms to the right. 
+3n + 0.5n-2n=+2-14-6

We simplify left and right side of the equation. 
+1.5n=-18

We divide both sides of the equation by 1.5 to get n. 
n=-12