3(n+2)+4(n+3)=

Solution for 3(n+2)+4(n+3)= equation:

Simplifying
3(n + 2) + 4(n + 3) = 0

Reorder the terms:
3(2 + n) + 4(n + 3) = 0
(2 * 3 + n * 3) + 4(n + 3) = 0
(6 + 3n) + 4(n + 3) = 0

Reorder the terms:
6 + 3n + 4(3 + n) = 0
6 + 3n + (3 * 4 + n * 4) = 0
6 + 3n + (12 + 4n) = 0

Reorder the terms:
6 + 12 + 3n + 4n = 0

Combine like terms: 6 + 12 = 18
18 + 3n + 4n = 0

Combine like terms: 3n + 4n = 7n
18 + 7n = 0

Solving
18 + 7n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + 7n = 0 + -18

Combine like terms: 18 + -18 = 0
0 + 7n = 0 + -18
7n = 0 + -18

Combine like terms: 0 + -18 = -18
7n = -18

Divide each side by '7'.
n = -2.571428571

Simplifying
n = -2.571428571