3(n+2)+4n=34

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Solution for 3(n+2)+4n=34 equation: 



3(n+2)+4n=34

We move all terms to the left:

3(n+2)+4n-(34)=0

We add all the numbers together, and all the variables

4n+3(n+2)-34=0

We multiply parentheses

4n+3n+6-34=0

We add all the numbers together, and all the variables

7n-28=0

We move all terms containing n to the left, all other terms to the right

7n=28

n=28/7

n=4

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