3(n+2)+4n=34

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Solution for 3(n+2)+4n=34 equation:



3(n+2)+4n=34
We move all terms to the left:
3(n+2)+4n-(34)=0
We add all the numbers together, and all the variables
4n+3(n+2)-34=0
We multiply parentheses
4n+3n+6-34=0
We add all the numbers together, and all the variables
7n-28=0
We move all terms containing n to the left, all other terms to the right
7n=28
n=28/7
n=4

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