3(n+2)+4n=4(n-2)-4

Solution for 3(n+2)+4n=4(n-2)-4 equation:

Simplifying
3(n + 2) + 4n = 4(n + -2) + -4

Reorder the terms:
3(2 + n) + 4n = 4(n + -2) + -4
(2 * 3 + n * 3) + 4n = 4(n + -2) + -4
(6 + 3n) + 4n = 4(n + -2) + -4

Combine like terms: 3n + 4n = 7n
6 + 7n = 4(n + -2) + -4

Reorder the terms:
6 + 7n = 4(-2 + n) + -4
6 + 7n = (-2 * 4 + n * 4) + -4
6 + 7n = (-8 + 4n) + -4

Reorder the terms:
6 + 7n = -8 + -4 + 4n

Combine like terms: -8 + -4 = -12
6 + 7n = -12 + 4n

Solving
6 + 7n = -12 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
6 + 7n + -4n = -12 + 4n + -4n

Combine like terms: 7n + -4n = 3n
6 + 3n = -12 + 4n + -4n

Combine like terms: 4n + -4n = 0
6 + 3n = -12 + 0
6 + 3n = -12

Add '-6' to each side of the equation.
6 + -6 + 3n = -12 + -6

Combine like terms: 6 + -6 = 0
0 + 3n = -12 + -6
3n = -12 + -6

Combine like terms: -12 + -6 = -18
3n = -18

Divide each side by '3'.
n = -6

Simplifying
n = -6