3(n+2)-2(n-2)=18

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Solution for 3(n+2)-2(n-2)=18 equation: 



3(n+2)-2(n-2)=18

We move all terms to the left:

3(n+2)-2(n-2)-(18)=0

We multiply parentheses

3n-2n+6+4-18=0

We add all the numbers together, and all the variables

n-8=0

We move all terms containing n to the left, all other terms to the right

n=8

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