3(n+2)-2=4(2n+3)

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Solution for 3(n+2)-2=4(2n+3) equation: 



3(n+2)-2=4(2n+3)

We move all terms to the left:

3(n+2)-2-(4(2n+3))=0

We multiply parentheses

3n-(4(2n+3))+6-2=0



We calculate terms in parentheses: -(4(2n+3)), so:

4(2n+3)

We multiply parentheses

8n+12

Back to the equation:

-(8n+12)



We add all the numbers together, and all the variables

3n-(8n+12)+4=0

We get rid of parentheses

3n-8n-12+4=0

We add all the numbers together, and all the variables

-5n-8=0

We move all terms containing n to the left, all other terms to the right

-5n=8

n=8/-5

n=-1+3/5

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