3(n+2)-5+n=5(n-3)+3n+4

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Solution for 3(n+2)-5+n=5(n-3)+3n+4 equation: 



3(n+2)-5+n=5(n-3)+3n+4

We move all terms to the left:

3(n+2)-5+n-(5(n-3)+3n+4)=0

We add all the numbers together, and all the variables

n+3(n+2)-(5(n-3)+3n+4)-5=0

We multiply parentheses

n+3n-(5(n-3)+3n+4)+6-5=0



We calculate terms in parentheses: -(5(n-3)+3n+4), so:

5(n-3)+3n+4

We add all the numbers together, and all the variables

3n+5(n-3)+4

We multiply parentheses

3n+5n-15+4

We add all the numbers together, and all the variables

8n-11

Back to the equation:

-(8n-11)



We add all the numbers together, and all the variables

4n-(8n-11)+1=0

We get rid of parentheses

4n-8n+11+1=0

We add all the numbers together, and all the variables

-4n+12=0

We move all terms containing n to the left, all other terms to the right

-4n=-12

n=-12/-4

n=+3

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