3(n+2)=125

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Solution for 3(n+2)=125 equation: 



3(n+2)=125

We move all terms to the left:

3(n+2)-(125)=0

We multiply parentheses

3n+6-125=0

We add all the numbers together, and all the variables

3n-119=0

We move all terms containing n to the left, all other terms to the right

3n=119

n=119/3

n=39+2/3

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