3(n+2)=2(1-n)

Solution for 3(n+2)=2(1-n) equation:

3(n+2)=2(1-n)

We move all terms to the left:

3(n+2)-(2(1-n))=0

We add all the numbers together, and all the variables

3(n+2)-(2(-1n+1))=0

We multiply parentheses

3n-(2(-1n+1))+6=0


We calculate terms in parentheses: -(2(-1n+1)), so:

2(-1n+1)

We multiply parentheses

-2n+2

Back to the equation:

-(-2n+2)


We get rid of parentheses

3n+2n-2+6=0

We add all the numbers together, and all the variables

5n+4=0

We move all terms containing n to the left, all other terms to the right

5n=-4

n=-4/5

n=-4/5