3(n+2)=2(5n-4)

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Solution for 3(n+2)=2(5n-4) equation: 



3(n+2)=2(5n-4)

We move all terms to the left:

3(n+2)-(2(5n-4))=0

We multiply parentheses

3n-(2(5n-4))+6=0



We calculate terms in parentheses: -(2(5n-4)), so:

2(5n-4)

We multiply parentheses

10n-8

Back to the equation:

-(10n-8)



We get rid of parentheses

3n-10n+8+6=0

We add all the numbers together, and all the variables

-7n+14=0

We move all terms containing n to the left, all other terms to the right

-7n=-14

n=-14/-7

n=+2

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