3(n+2)=4(n-1)

Solution for 3(n+2)=4(n-1) equation:

Simplifying
3(n + 2) = 4(n + -1)

Reorder the terms:
3(2 + n) = 4(n + -1)
(2 * 3 + n * 3) = 4(n + -1)
(6 + 3n) = 4(n + -1)

Reorder the terms:
6 + 3n = 4(-1 + n)
6 + 3n = (-1 * 4 + n * 4)
6 + 3n = (-4 + 4n)

Solving
6 + 3n = -4 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
6 + 3n + -4n = -4 + 4n + -4n

Combine like terms: 3n + -4n = -1n
6 + -1n = -4 + 4n + -4n

Combine like terms: 4n + -4n = 0
6 + -1n = -4 + 0
6 + -1n = -4

Add '-6' to each side of the equation.
6 + -6 + -1n = -4 + -6

Combine like terms: 6 + -6 = 0
0 + -1n = -4 + -6
-1n = -4 + -6

Combine like terms: -4 + -6 = -10
-1n = -10

Divide each side by '-1'.
n = 10

Simplifying
n = 10