3(n+2)=4n+1-2n

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Solution for 3(n+2)=4n+1-2n equation: 



3(n+2)=4n+1-2n

We move all terms to the left:

3(n+2)-(4n+1-2n)=0

We add all the numbers together, and all the variables

3(n+2)-(2n+1)=0

We multiply parentheses

3n-(2n+1)+6=0

We get rid of parentheses

3n-2n-1+6=0

We add all the numbers together, and all the variables

n+5=0

We move all terms containing n to the left, all other terms to the right

n=-5

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