3(n+2)=8(6-n)

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Solution for 3(n+2)=8(6-n) equation: 



3(n+2)=8(6-n)

We move all terms to the left:

3(n+2)-(8(6-n))=0

We add all the numbers together, and all the variables

3(n+2)-(8(-1n+6))=0

We multiply parentheses

3n-(8(-1n+6))+6=0



We calculate terms in parentheses: -(8(-1n+6)), so:

8(-1n+6)

We multiply parentheses

-8n+48

Back to the equation:

-(-8n+48)



We get rid of parentheses

3n+8n-48+6=0

We add all the numbers together, and all the variables

11n-42=0

We move all terms containing n to the left, all other terms to the right

11n=42

n=42/11

n=3+9/11

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