3(n+2)=96(6-n)

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Solution for 3(n+2)=96(6-n) equation: 



3(n+2)=96(6-n)

We move all terms to the left:

3(n+2)-(96(6-n))=0

We add all the numbers together, and all the variables

3(n+2)-(96(-1n+6))=0

We multiply parentheses

3n-(96(-1n+6))+6=0



We calculate terms in parentheses: -(96(-1n+6)), so:

96(-1n+6)

We multiply parentheses

-96n+576

Back to the equation:

-(-96n+576)



We get rid of parentheses

3n+96n-576+6=0

We add all the numbers together, and all the variables

99n-570=0

We move all terms containing n to the left, all other terms to the right

99n=570

n=570/99

n=5+25/33

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