3(n+2)=m(m-2)

Solution for 3(n+2)=m(m-2) equation:

Simplifying
3(n + 2) = m(m + -2)

Reorder the terms:
3(2 + n) = m(m + -2)
(2 * 3 + n * 3) = m(m + -2)
(6 + 3n) = m(m + -2)

Reorder the terms:
6 + 3n = m(-2 + m)
6 + 3n = (-2 * m + m * m)
6 + 3n = (-2m + m2)

Solving
6 + 3n = -2m + m2

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3n = -2m + -6 + m2

Combine like terms: 6 + -6 = 0
0 + 3n = -2m + -6 + m2
3n = -2m + -6 + m2

Reorder the terms:
3n = -6 + -2m + m2

Divide each side by '3'.
n = -2 + -0.6666666667m + 0.3333333333m2

Simplifying
n = -2 + -0.6666666667m + 0.3333333333m2