3(n+3)+2(n+2)+n+1=38

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Solution for 3(n+3)+2(n+2)+n+1=38 equation: 



3(n+3)+2(n+2)+n+1=38

We move all terms to the left:

3(n+3)+2(n+2)+n+1-(38)=0

We add all the numbers together, and all the variables

n+3(n+3)+2(n+2)-37=0

We multiply parentheses

n+3n+2n+9+4-37=0

We add all the numbers together, and all the variables

6n-24=0

We move all terms containing n to the left, all other terms to the right

6n=24

n=24/6

n=4

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