3(n+3)+4n=3(2n+6)+n-9

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Solution for 3(n+3)+4n=3(2n+6)+n-9 equation: 



3(n+3)+4n=3(2n+6)+n-9

We move all terms to the left:

3(n+3)+4n-(3(2n+6)+n-9)=0

We add all the numbers together, and all the variables

4n+3(n+3)-(3(2n+6)+n-9)=0

We multiply parentheses

4n+3n-(3(2n+6)+n-9)+9=0



We calculate terms in parentheses: -(3(2n+6)+n-9), so:

3(2n+6)+n-9

We add all the numbers together, and all the variables

n+3(2n+6)-9

We multiply parentheses

n+6n+18-9

We add all the numbers together, and all the variables

7n+9

Back to the equation:

-(7n+9)



We add all the numbers together, and all the variables

7n-(7n+9)+9=0

We get rid of parentheses

7n-7n-9+9=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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