3(n+3)-2n+2(n+4)=65

Solution for 3(n+3)-2n+2(n+4)=65 equation:

3(n+3)-2n+2(n+4)=65

We simplify the equation to the form, which is simple to understand 
3(n+3)-2n+2(n+4)=65

Reorder the terms in parentheses
+(+3n+9)-2n+2*(n+4)=65

Remove unnecessary parentheses
+3n+9-2n+2+*(+n+4+)=+65

Reorder the terms in parentheses
+3n+9-2n+(+2n+8)=65

Remove unnecessary parentheses
+3n+9-2n+2n+8=+65

We move all terms containing n to the left and all other terms to the right. 
+3n-2n+2n=+65-9-8

We simplify left and right side of the equation. 
+3n=+48

We divide both sides of the equation by 3 to get n. 
n=16