3(n+3)=25+2n

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Solution for 3(n+3)=25+2n equation: 



3(n+3)=25+2n

We move all terms to the left:

3(n+3)-(25+2n)=0

We add all the numbers together, and all the variables

3(n+3)-(2n+25)=0

We multiply parentheses

3n-(2n+25)+9=0

We get rid of parentheses

3n-2n-25+9=0

We add all the numbers together, and all the variables

n-16=0

We move all terms containing n to the left, all other terms to the right

n=16

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