3(n+3)=4n+30

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Solution for 3(n+3)=4n+30 equation: 



3(n+3)=4n+30

We move all terms to the left:

3(n+3)-(4n+30)=0

We multiply parentheses

3n-(4n+30)+9=0

We get rid of parentheses

3n-4n-30+9=0

We add all the numbers together, and all the variables

-1n-21=0

We move all terms containing n to the left, all other terms to the right

-n=21

n=21/-1

n=-21

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