3(n+4)+22=3(n+12)-2

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Solution for 3(n+4)+22=3(n+12)-2 equation: 



3(n+4)+22=3(n+12)-2

We move all terms to the left:

3(n+4)+22-(3(n+12)-2)=0

We multiply parentheses

3n-(3(n+12)-2)+12+22=0



We calculate terms in parentheses: -(3(n+12)-2), so:

3(n+12)-2

We multiply parentheses

3n+36-2

We add all the numbers together, and all the variables

3n+34

Back to the equation:

-(3n+34)



We add all the numbers together, and all the variables

3n-(3n+34)+34=0

We get rid of parentheses

3n-3n-34+34=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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