3(n+4)+4(n-8)=24n+36

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Solution for 3(n+4)+4(n-8)=24n+36 equation: 



3(n+4)+4(n-8)=24n+36

We move all terms to the left:

3(n+4)+4(n-8)-(24n+36)=0

We multiply parentheses

3n+4n-(24n+36)+12-32=0

We get rid of parentheses

3n+4n-24n-36+12-32=0

We add all the numbers together, and all the variables

-17n-56=0

We move all terms containing n to the left, all other terms to the right

-17n=56

n=56/-17

n=-3+5/17

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