3(n+4)+8=n/2

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Solution for 3(n+4)+8=n/2 equation: 



3(n+4)+8=n/2

We move all terms to the left:

3(n+4)+8-(n/2)=0

We add all the numbers together, and all the variables

3(n+4)-(+n/2)+8=0

We multiply parentheses

3n-(+n/2)+12+8=0

We get rid of parentheses

3n-n/2+12+8=0

We multiply all the terms by the denominator


3n*2-n+12*2+8*2=0

We add all the numbers together, and all the variables

-1n+3n*2+40=0

Wy multiply elements

-1n+6n+40=0

We add all the numbers together, and all the variables

5n+40=0

We move all terms containing n to the left, all other terms to the right

5n=-40

n=-40/5

n=-8

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