3(n+4)+n=-2(n+6)

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Solution for 3(n+4)+n=-2(n+6) equation: 



3(n+4)+n=-2(n+6)

We move all terms to the left:

3(n+4)+n-(-2(n+6))=0

We add all the numbers together, and all the variables

n+3(n+4)-(-2(n+6))=0

We multiply parentheses

n+3n-(-2(n+6))+12=0



We calculate terms in parentheses: -(-2(n+6)), so:

-2(n+6)

We multiply parentheses

-2n-12

Back to the equation:

-(-2n-12)



We add all the numbers together, and all the variables

4n-(-2n-12)+12=0

We get rid of parentheses

4n+2n+12+12=0

We add all the numbers together, and all the variables

6n+24=0

We move all terms containing n to the left, all other terms to the right

6n=-24

n=-24/6

n=-4

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