3(n+4)+n=-2(n+60

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Solution for 3(n+4)+n=-2(n+60 equation: 



3(n+4)+n=-2(n+60

We move all terms to the left:

3(n+4)+n-(-2(n+60)=0

We add all the numbers together, and all the variables

n+3(n+4)-(-2(n+60)=0

We multiply parentheses

n+3n-(-2(n+60)+12=0

We add all the numbers together, and all the variables

4n-(-2(n+60)+12=0

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