3(n+4)-(n-2)=24

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Solution for 3(n+4)-(n-2)=24 equation:


Simplifying
3(n + 4) + -1(n + -2) = 24

Reorder the terms:
3(4 + n) + -1(n + -2) = 24
(4 * 3 + n * 3) + -1(n + -2) = 24
(12 + 3n) + -1(n + -2) = 24

Reorder the terms:
12 + 3n + -1(-2 + n) = 24
12 + 3n + (-2 * -1 + n * -1) = 24
12 + 3n + (2 + -1n) = 24

Reorder the terms:
12 + 2 + 3n + -1n = 24

Combine like terms: 12 + 2 = 14
14 + 3n + -1n = 24

Combine like terms: 3n + -1n = 2n
14 + 2n = 24

Solving
14 + 2n = 24

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 2n = 24 + -14

Combine like terms: 14 + -14 = 0
0 + 2n = 24 + -14
2n = 24 + -14

Combine like terms: 24 + -14 = 10
2n = 10

Divide each side by '2'.
n = 5

Simplifying
n = 5

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