3(n+4)-8=1/2n

Solution for 3(n+4)-8=1/2n equation:

3(n+4)-8=1/2n

We move all terms to the left:

3(n+4)-8-(1/2n)=0


Domain of the equation: 2n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

3(n+4)-(+1/2n)-8=0

We multiply parentheses

3n-(+1/2n)+12-8=0

We get rid of parentheses

3n-1/2n+12-8=0

We multiply all the terms by the denominator


3n*2n+12*2n-8*2n-1=0

Wy multiply elements

6n^2+24n-16n-1=0

We add all the numbers together, and all the variables

6n^2+8n-1=0

a = 6; b = 8; c = -1;
Δ = b2-4ac
Δ = 82-4·6·(-1)
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{22}}{2*6}=\frac{-8-2\sqrt{22}}{12}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{22}}{2*6}=\frac{-8+2\sqrt{22}}{12}
$