3(n+4)=1/2(-6n+12)

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Solution for 3(n+4)=1/2(-6n+12) equation: 



3(n+4)=1/2(-6n+12)

We move all terms to the left:

3(n+4)-(1/2(-6n+12))=0



Domain of the equation: 2(-6n+12))!=0

n∈R



We multiply parentheses

3n-(1/2(-6n+12))+12=0

We multiply all the terms by the denominator


3n*2(-6n+12))-(1+12*2(-6n+12))=0

Wy multiply elements

6n^2(-+24n(-=0

We use the square of the difference formula

6n^2(-24n(-=0

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