3(n+4)=1/2(6n+4)3n+12=

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Solution for 3(n+4)=1/2(6n+4)3n+12= equation: 



3(n+4)=1/2(6n+4)3n+12=

We move all terms to the left:

3(n+4)-(1/2(6n+4)3n+12)=0



Domain of the equation: 2(6n+4)3n+12)!=0

n∈R



We multiply parentheses

3n-(1/2(6n+4)3n+12)+12=0

We multiply all the terms by the denominator


3n*2(6n+4)3n+12*2(6n+4)3n+12)-(1+12)=0

We add all the numbers together, and all the variables

3n*2(6n+4)3n+12*2(6n+4)3n+12)-13=0

We add all the numbers together, and all the variables

3n*2(6n+4)3n+12*2(6n+4)3n=0

Wy multiply elements

6n^2(6+24n(6=0

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