3(n+4)=2+4(n+1)

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Solution for 3(n+4)=2+4(n+1) equation: 



3(n+4)=2+4(n+1)

We move all terms to the left:

3(n+4)-(2+4(n+1))=0

We multiply parentheses

3n-(2+4(n+1))+12=0



We calculate terms in parentheses: -(2+4(n+1)), so:

2+4(n+1)

determiningTheFunctionDomain
4(n+1)+2

We multiply parentheses

4n+4+2

We add all the numbers together, and all the variables

4n+6

Back to the equation:

-(4n+6)



We get rid of parentheses

3n-4n-6+12=0

We add all the numbers together, and all the variables

-1n+6=0

We move all terms containing n to the left, all other terms to the right

-n=-6

n=-6/-1

n=+6

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