3(n+4)=24+2n

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Solution for 3(n+4)=24+2n equation:



3(n+4)=24+2n
We move all terms to the left:
3(n+4)-(24+2n)=0
We add all the numbers together, and all the variables
3(n+4)-(2n+24)=0
We multiply parentheses
3n-(2n+24)+12=0
We get rid of parentheses
3n-2n-24+12=0
We add all the numbers together, and all the variables
n-12=0
We move all terms containing n to the left, all other terms to the right
n=12

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