3(n+4)=5(n+5)-5

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Solution for 3(n+4)=5(n+5)-5 equation: 



3(n+4)=5(n+5)-5

We move all terms to the left:

3(n+4)-(5(n+5)-5)=0

We multiply parentheses

3n-(5(n+5)-5)+12=0



We calculate terms in parentheses: -(5(n+5)-5), so:

5(n+5)-5

We multiply parentheses

5n+25-5

We add all the numbers together, and all the variables

5n+20

Back to the equation:

-(5n+20)



We get rid of parentheses

3n-5n-20+12=0

We add all the numbers together, and all the variables

-2n-8=0

We move all terms containing n to the left, all other terms to the right

-2n=8

n=8/-2

n=-4

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