3(n+4)=n+20

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Solution for 3(n+4)=n+20 equation:


Simplifying
3(n + 4) = n + 20

Reorder the terms:
3(4 + n) = n + 20
(4 * 3 + n * 3) = n + 20
(12 + 3n) = n + 20

Reorder the terms:
12 + 3n = 20 + n

Solving
12 + 3n = 20 + n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1n' to each side of the equation.
12 + 3n + -1n = 20 + n + -1n

Combine like terms: 3n + -1n = 2n
12 + 2n = 20 + n + -1n

Combine like terms: n + -1n = 0
12 + 2n = 20 + 0
12 + 2n = 20

Add '-12' to each side of the equation.
12 + -12 + 2n = 20 + -12

Combine like terms: 12 + -12 = 0
0 + 2n = 20 + -12
2n = 20 + -12

Combine like terms: 20 + -12 = 8
2n = 8

Divide each side by '2'.
n = 4

Simplifying
n = 4

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