3(n+4)=n-9

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Solution for 3(n+4)=n-9 equation: 



3(n+4)=n-9

We move all terms to the left:

3(n+4)-(n-9)=0

We multiply parentheses

3n-(n-9)+12=0

We get rid of parentheses

3n-n+9+12=0

We add all the numbers together, and all the variables

2n+21=0

We move all terms containing n to the left, all other terms to the right

2n=-21

n=-21/2

n=-10+1/2

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